📰 “Your life is a story of transition. You are always leaving one chapter behind while moving on to the next.” – Anonymous

                August 2, 2021

            📰 “Your life is a story of transition. You are always leaving one chapter behind while moving on to the next.” – Anonymous

            The Coding Puzzle  🧩
Last week's puzzle:
Given a string, write a function to check if it is a permutation of a palindrome. A palindrome is a word or phrase that is the same forwards and backwards. A permutation is a rearrangement of letters. The palindrome does not need to be limited to just dictionary words.
Solution for last week's problem: 
def canFormPalindrome(s):
    bitvector = 0
    for str in s:
        bitvector ^= 1 << ord(str)
    return bitvector == 0 or bitvector & (bitvector - 1) == 0

#s = input()  
if canFormPalindrome("racecar"):
    print('Yes')
else:
    print('No')

This week's puzzle:
Given the array nums, for each nums[i] find out how many numbers in the array are smaller than it. That is, for each nums[i] you have to count the number of valid j's such that j != i and nums[j] < nums[i].
Return the answer in an array.
Example 1:
Input: nums = [6,5,4,8]
Output: [2,1,0,3]
Example 2:
Input: nums = [7,7,7,7]
Output: [0,0,0,0]
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